Haddock fixes.
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@ -84,7 +84,7 @@ class (Functor query, Applicative query, Monad query) =>
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--
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-- @
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-- select $
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-- from $ \(foo `InnerJoin` bar) -> do
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-- from $ \\(foo ``InnerJoin`` bar) -> do
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-- on (foo ^. FooId ==. bar ^. BarFooId)
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-- ...
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-- @
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@ -96,7 +96,7 @@ class (Functor query, Applicative query, Monad query) =>
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--
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-- @
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-- select $
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-- from $ \(foo `InnerJoin` bar `InnerJoin` baz) -> do
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-- from $ \\(foo ``InnerJoin`` bar ``InnerJoin`` baz) -> do
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-- on (baz ^. BazId ==. bar ^. BarBazId)
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-- on (foo ^. FooId ==. bar ^. BarFooId)
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-- ...
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@ -107,15 +107,13 @@ class (Functor query, Applicative query, Monad query) =>
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--
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-- @
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-- let query1 =
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-- from $ \(foo `InnerJoin` bar) -> do
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-- from $ \\(foo ``InnerJoin`` bar) -> do
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-- on (foo ^. FooId ==. bar ^. BarFooId)
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--
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-- query2 =
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-- from $ \(mbaz `LeftOuterJoin` quux) -> do
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-- from $ \\(mbaz ``LeftOuterJoin`` quux) -> do
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-- return (mbaz ?. BazName, quux)
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--
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-- test1 = (,) <$> query1 <*> query2
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-- test2 = flip (,) <$> query2 <*> query1
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-- test1 = (,) \<$\> query1 \<*\> query2
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-- test2 = flip (,) \<$\> query2 \<*\> query1
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-- @
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--
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-- If the order was *not* reversed, then @test2@ would be
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@ -217,7 +215,7 @@ data CrossJoin a b = a `CrossJoin` b
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--
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-- @
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-- select $
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-- from $ \(person `LeftOuterJoin` pet) ->
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-- from $ \\(person ``LeftOuterJoin`` pet) ->
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-- ...
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-- @
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--
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@ -228,6 +226,8 @@ data CrossJoin a b = a `CrossJoin` b
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-- FROM Person LEFT OUTER JOIN Pet
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-- ...
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-- @
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--
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-- See also: 'from'.
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data LeftOuterJoin a b = a `LeftOuterJoin` b
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-- | Data type that represents a @RIGHT OUTER JOIN@ (see 'LeftOuterJoin' for an example).
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